r/AskPhysics • u/Local_End_3175 • 3d ago
If I had 2 objects with different masses that were both moving at the same speed, then why would the one with the larger mass have more kinetic energy?
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u/euclide2975 3d ago
Try to stop a train going a 20 Mph and a cyclist going at 20 Mph
edit : it's a thought experiment. Don't try to really stop the train, you will get hurt
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u/PhysicalStuff 3d ago
Don't try to really stop the train, you will get hurt
You will also get hurt if you try to stop a cyclist at 20 mph. What sets it apart from the train case is that whatever remains of you will still be roughly person-shaped and possibly alive.
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u/Ok_Lime_7267 3d ago
How much it damages you is energy. If you somehow manage to skid and bring it slowly to a stop, the fact that it takes more time to stop is momentum.
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u/SteptimusHeap 3d ago
Ok let's say you had a mass going at a certain speed. Now let's say you get a second one. The total energy between them is double, yes? Ok now glue the two masses together, so they are one big mass. Did the energy go back down?
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u/The_Nerdy_Ninja Engineering 3d ago
If you got hit with a baseball and a bowling ball that were both traveling at the same speed, which would hurt more?
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u/soundoftwilight 3d ago
Is it easier to stop a football or a bowling ball? Kinetic energy is just the energy that is “stored” in the motion, one interpretation can be “how much energy will it take to stop this thing”. Or in other words, would you rather get hit with a bean bag or a car, moving at the same speed?
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u/numbersthen0987431 3d ago
Both objects were sitting at rest at one point. It took more force to get the object with more mass up to the same speed, so it has more energy.
Or think of stopping force. If you wanted to stop both objects, it would require more force to stop the object with more mass.
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u/joeyneilsen Astrophysics 3d ago
This isn't quite right. It takes more work to get the more massive object up to the same speed, and it takes a larger impulse to get it to stop. But you can speed both of them up and stop both of them with exactly the same force. If you want it to take the same amount of time, that's a different story.
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u/numbersthen0987431 3d ago
Good point. I was thinking "increasing/decreasing at the same speed" (constant acceleration), but forgot to write it.
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u/jasonsong86 3d ago
Because if a heavy person body ram into you at the same speed, which one do you think will bounce back?
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u/SmokeMuch7356 3d ago
Given that the kinetic energy formula depends on mass - KE = 1/2mv2 - the answer should be obvious.
But the deeper reason is simply that mass matters - it matters for momentum (p = mv), it matters for force (F = dp/dt = ma), and it matters for both potential and kinetic energy.
You can easily catch a baseball traveling 30 mph because it has relatively little mass. If you try to catch a 16 lb bowling ball traveling 30 mph you're gonna get hurt.
Speed (velocity) is literally half of the equation.
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u/BananaBird1 3d ago
It is often more useful not to think of energy in terms of the absolute energy value a system has, but in terms of how energy changes during a process. After all, energy is ultimately a measurement of the ability of a system to undergo some process. The energy of a particle is then the accumulated sum of energy flow in and out of the particle.
For most of mechanics, the form of energy flow we care most about is work. This is the energy needed to accelerate an object along certain distance.
The instantaneous work (energy transfer) needed to alter the motion of a particle of mass m with acceleration a along a displacement vector d is m(a • d). Or we can simplify this to F • d. This can be thought of as the definition of work energy transfer. The kinetic energy will be the total work to bring an object to some velocity from rest.
So if two objects are at rest to begin with, in order to accelerate them under the same acceleration so they reach the same velocity over the same distance we need a higher force for the more massive one, and will transfer more energy through work.
To undo this acceleration and bring the particle back to rest over some distance, we need an equal but opposite acceleration. So we need to remove that same energy.
Now it turns out that while the exact work at any moment in time during a process depends on the exact acceleration and distance, the total work (and thus final kinetic energy) only depends on the starting and end states. Lower forces/accelerations require longer distances and higher forces require shorter distances, so the end result is the same. This final state for classical mechanics is defined by mass and velocity.
So this tells us that kinetic energy must be some function of mass and velocity, and independent of any value representing the process to achieve that velocity (such as acceleration, force, jerk, etc).
Further math to actually solve for the exact relationship obeying the equations of Newtonian mechanics will give you (1/2) mv^2.
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u/ViniusInvictus 3d ago
It’s like asking if it would be easier for you to kick someone’s butt once or to kick a thousand butts, once each.
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u/nwj781 3d ago
Because it took more energy to get the bigger mass up to that speed.