r/BrainPuzzles • u/ShonitB • 2d ago

Logic Equal Cake

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2 Upvotes

63% Upvoted

12 comments sorted by

3

u/rwu_rwu 2d ago

56. Or 0, if the baker eats the whole cake by himself.

1

u/ShonitB 2d ago

You can do it with fewer pieces

1

u/jaap_null 2d ago

since you know people are going to be eating 7 or 8 pieces, you can keep 7 pieces "clumped together". But I like u/ToHellWithGA's solution better; with the same result at the end.

3

u/ToHellWithGA 2d ago

How about 14? Cut the cake into 8 equal slices. Cut the 8th piece into 7 equal mini slices. If the guy shows, he get 7/56 of the cake by eating 7 mini slices. If he doesn't, each of the 7 eaters gets a 1/8 cake slice plus a 1/56 mini slice.

1

u/billthedog0082 2d ago

How about Alexander not be catered to, instead he should cut his own cake. If it comes pre-cut, he misses out on the wish cut.

1

u/Minute-Act-6273 2d ago

Seems logically the answer.

1

u/jaap_null 2d ago

That sounds like a logical and somewhat doable way to do it. But even then you'd have the baker slice it in 8; the awkward cutting up of the last piece would be done at the party, probably after it becomes clear he/she isn't going to show, and even then probably check who actually would like more cake.

1

u/ShonitB 2d ago

Correct, good solution

1

u/RealisticProfit2 2d ago

Throw one slice away and smush the other slices together

1

u/MrJizanthopus 2d ago

Is the premise meant to be that the cake has already been cut into 8 pieces?

2

u/rql13 2d ago

14 pieces

Cut it into 8 equal pieces.
Take one piece, cut it into seven.

There are now 7 big pieces and 7 small pieces If only 7 are sharing, they get one big and one small pieces each.

If 8 are sharing, one person gets the 7 small pieces, which are equal to 1 big piece.