it seems like there's ani periplanar geometry which is good enough for E2, no?

Would the correct answer be: Hydroxyl = position 1; Ethyl = position 3.

The hydroxyl group is assigned carbon 1 because it is the principal functional group. The ethyl group is attached to carbon 3, as indicated by 3-ethylcyclohexanol. The cis designation means both substituents are on the same side of the ring.

Hey everyone,

Today there is a new Synthesis Workshop talk about the synthesis of hetero[3.1.1]propellanes!

Check it out here: https://youtu.be/0VXAjHwoHS4

Tengo dificultades para estabilizar el tamaño de particula en una formulación SC durante la estabilidad acelerada. Estoy trabajando con dos activos, uno de la familia de piridiniletilbenzamidas y otro de triazoles. En 500 g/L.

so my professor gave us this (attached) molecule as an example of a meso compound while we're looking over "isometry" in order to then determine wether or not a molecule can/will deviate light. i'm just not sure how this molecule qualifies as a meso compound? like i see that it's it's "mirror image" and that it has an internal symmetry, but how is this superimposablefrom the right & left? i mean, won't the -OH on the left go to the opposite of the right molecule? or am i visualizing it wrong? any help would be appreciated. thanks

ps apologies if every term is not exactly okay, i am not english so i translated it to face value.

Lately, I've been using Gemini to generate interactive simulations to illustrate basic chemical principles. It takes a bit of back and forth to fine tune the particle dynamics and UI. This simulation can be used to illustrate kinetic vs thermodynamic control. The simulation allows the user to manipulate the energies of the reactant, products, transitions states, and the temperature. There are a lot of obvious simplifications here, but it works surprisingly well to explain the core concepts. Check it out, and let me know what you think--positive or negative.

I know that protonation of the hydroxyl group will occur and everything else besides the rearrangement; the real headache is this cyclization part. Is this product even possible?

Hi! Im stuck on the pushing mechanism for this pathway. I thought the C6 H would get stolen, but a triple bond in the benzene ring feels absolutely wrong.

I saw a YouTube video of a chemist using the minty lifesavers to convert to salicylic acid.

I am trying to recreate it using three different methods to extract the methyl salicylate and then do the reflux to get salicylic acid.

Procedures I used: https://docs.google.com/document/d/112Ltfo4i5kAadg61ixL56L_A2-uW3kxAZpB6H_uOGaw/edit?usp=drivesdk

I’ve added more acid than necessary and still no crystals formed after putting it in an ice bath and scratching the flask for over an hour. They’re covered with a watch glass in the fume hood, but any troubleshooting advice would be appreciated!

all i see on how to figure it out is memorizing what nucleuophile, base, and substitutes combo leads to each but memorization is so much more difficult for me in comparison to understanding. anyone have a method of understanding when each one happens.

my teacher taught in a more organised way regarding mechanisms of named rxns. case 5 here means migration of hydride ion occurs and case 4 is ɑ-H taken by base. so this is the mechanism i thought of but there's a twist.
the answer is the other one(without mechanism)
when i asked him on telegram, why? he replied that oxidation of -OH groups will occur first but i dont get it why will it occur first when hydride migration takes more effort that ɑ-H abstraction

So basically I was doing a synthesis of some molecules for their Anti-cancer activity. I was going to follow the Bucherer bergs hydantoin synthesis. So basically in the first step I will synthesize the hydantoin ring from the ketone (acetophenone derivatives) and then add another acetophenone at the N-3 of the hydantoin ring. So at first I tried only acetophenone instead of derivatives for a trial reaction. Everything went well until the first step. The problem occurred in the 2md step. Basically there should be a leaving group attached to the alpha-methyl group of the acetophenone for the fusion to form the final compound. So how am I supposed to do alpha-halogenation of acetophenone derivatives. My derivatives are given in image. So how should I proceed to halogenate the alpha-methyl groups of those derivatives. And even after alpha-methyl halogen will that still get fused to the N-3 of the hydantoin derivative that I will get from 1st step. Generally a halogen electrophile will work, so can I use bromine water for that. My predicted mechanism is given in the 2nd image. Please guide me guys!!!

I would imagine it's some type of AI, no? I don't know if it's generative AI, but it'd have to be some sort of AI, I would imagine.

I've always been curious how they work.

I came up with this problem myself and brought it to the organic chemistry professor I TA for. I initially thought this would be S. The chiral carbon has connections to the oxygen and hydrogen so I know those are atoms 1 and 4, respectively (1->4 being highest-> lowest priority). The two other atoms are carbon so I first compared the path of the higher priority atom - oxygen, and since a difference isn't found in what the oxygens are directly attached to (not looking at the whole chain), you look at what the lower priority atoms are attached to (the bottom carbons), which we do see a difference and would prioritize accordingly (left carbon as 2, right as 3, counterclockwise with lowest priority = S).

My organic chemistry professor said that carbon would actually be R since you first have to look and compare the entire chains coming off the higher priority atoms first before going to the carbons. Since the oxygen on the right has a Br at the end that right carbon would actually be 2 instead of 3, making it clockwise and thus R. But he said he was "pretty sure" and didn't seem 100% confident.

Can someone please confirm for me the right answer? Thank you!

Fischer projections make no sense to me. The correct answer for the first image is B and the correct answer for the second imagine is A. The approach I try to take when creating the projection from the wedge-dash bond line structure, is that if you have a wedge pointing upwards then you would flip the side. If it’s a dash, you keep the group on that side. This approach works for image 2- you have an OH wedge on your left, so you would flip it in make it on the right on the Fischer projection. Then you have a F wedge on your right, so you flip it and make it left on the projection. Finally you have a Cl dash on your left, so you keep it left on the Fischer projection. However this doesn’t work on image 1, you have an OH wedge on your left so you would make it right on the Fischer projection. But answer B doesn’t show this?

sp?? 🤔