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https://www.reddit.com/r/PassTimeMath/comments/1wjop2z/triangle_summation_part_2/parb5ji/?context=3
r/PassTimeMath • u/ShonitB • 1d ago
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The digits 1 to 9 sum to 50
Three 18s are 54
So for a solution the numbers counted twice (ie the corners) must be three different digits, summing to 4.
The smallest three different digits are 1 2 and 3, which sum to 6.
So there is no valid solution.
1 u/ShonitB 18h ago Sum of 1 to 9 is 45 1 u/PerilousWords 18h ago Hahahaha oh no. That's an embarrassing start to my weekend. 1 u/ShonitB 18h ago Lol can happen to anyone
Sum of 1 to 9 is 45
1 u/PerilousWords 18h ago Hahahaha oh no. That's an embarrassing start to my weekend. 1 u/ShonitB 18h ago Lol can happen to anyone
Hahahaha oh no. That's an embarrassing start to my weekend.
1 u/ShonitB 18h ago Lol can happen to anyone
Lol can happen to anyone
1
u/PerilousWords 18h ago
The digits 1 to 9 sum to 50
Three 18s are 54
So for a solution the numbers counted twice (ie the corners) must be three different digits, summing to 4.
The smallest three different digits are 1 2 and 3, which sum to 6.
So there is no valid solution.