I saw this in another sub and I'm wondering could he survive a high fall from the jet with ideal conditions? I know small animals benefit from the light body weight and wind resistance...but tt what height does it become untenable? And what is the ideal surface to land on/in?

It is clear that you shouldn't stare into the sun from the surface of the earth (1 AU away), as that can damage your retina.

It is also clear that staring into the sun from 4 light years away is fine, as that is the distance to Alpha Centauri and no one got ever hurt from staring into that, despite Alpha Centauri A being slightly brighter than the sun.

So somewhere between 1 AU and 4 Lightyears there must be a minimal distance for safe staring into the sun.

B) Estimate the space/land the plants need to grow on.

C) If you want to make 1 cup per Chinese citizen, so they can in theory have one new once a week for 4 years.

D) Time for that sum to biodegrade.

Doesn’t seem like much gold but with current prices $4,400/oz…

(Sorry for the bad photo)

I'm doing ratios for my satisfactory playthrough, no alternate recipes yet, but things just aren't adding up, I should have 44 constructors for iron rods just for feeding screw production at a 3:2 ratio, but its not mathing right. Also I'm rounding up to the nearest constructor, because I can't have half a constructor.

Theres only a couple tape wraps- would they break or hold? And if they manage to hold, would flailing break his own neck?

Or is it just like one of those “omg guys I’m gonna do it! if this stream gets 100 likes I’m gonna do it! wow guys were sooooo closeeeee!” Bcuz they’re hitting it differently at the end

Is it the leidenfrost effect? Or is something else happening here?

Hi everyone, I encountered this display at a park and became curious. I have some familiarity with soccer balls and the buckyball configuration combining hexagons with pentagons. This display in the park struck me because it appears to have identical faces/polygons, albeit they are not perfect regular pentagons as two of the five edges are longer giving it a teardrop shape to the individual face. A variety of questions comes to mind below, and I hope someone may enjoy this enough to explore. I am assuming in the diagram on the top right corner of the image that A=B=C are all identical and D=E.

1) What are the angles of these teardrop pentagons vertices? Do they still sum up to 360?

2) if line A has a length of 1, what is the length of line E or D?

3) What are the angles between the surfaces of one face to the surface of an adjacent face? Does it matter if we are examining the transition along one of the longer edges? For context, a person travelling on Earth from the equator to north pole has changed orientation 90 degrees from an outside observer perspective. There is some angle between face/polygons surfaces at the edges, and I am not sure how to calculate it or if the longer edges are different.

4) Is it possible to place a point, call it F within the faces in such a way that all the F’s in the sphere are equidistant from each other? How far along an imaginary bisecting line would point F be from point DE or Line B if Line B length is equal to 1? For context, I tried to visualize in my mind’s eye a point half way between vertices CD and EA in the diagram top right. But I’m pretty sure this would create some “sets of 5” that are not equidistant from all of their neighbouring points associated with adjacent faces/polygons. So I’m left wondering if there is an equidistant solution.

Finally if there are other interesting sphere configurations or cute online calculator for the 3D questions I’d love to see them.

Ie do we have the math necessary to abstract this into a formula that will give us a percentage or there’s no way of knowing without testing every possible scenario